Semester : II
Infix to Postfix Conversion
X is an arithmetic expression written in infix notation.
This algorithm finds the equivalent post-fix expression Y.
1. Scan X from left to right
and repeat Step 2 to 5 for each element of X until the Stack is empty.
2. If an operand is
encountered, add it to Y.
3. If a left parenthesis is
encountered, push it onto Stack.
4. If an operator is
encountered ,then:
a.
Pop from Stack and add each operator which has the same precedence
as or higher precedence than scanned operator to Y.
b.
Add the scanned operator to Stack.
5. If a right parenthesis
is encountered ,then:
a.
Pop each operator from the Stack until a left parenthesis is
encountered and add it to Y.
b.
Remove the left Parenthesis
Let’s take an example to better understand the algorithm
Evaluation of Post-fix expression
·
While reading the
expression from left to right, push the element in the stack if it is an
operand.
·
Pop the two operands from
the stack, if the element is an operator and then evaluate it.
· Push back the result of the evaluation. Repeat it till the end of the expression.
Algorithm
1. Add ) to postfix expression.
2. Read postfix expression Left to Right until ) encountered
3. If operand is encountered, push it onto Stack
4. If operator is encountered, Pop two elements
a. A -> Top element
b. B-> Next to Top element
c. Evaluate B operator A
d. Push B operator A onto Stack
Example
Expression: 456*+
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